MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
aditya kulkarni Grade: 11
        

A uniform rod of  length 1m is placed on a table so that 0.2m projects over the edge. if the weight of the rod is 100, find the greatest weight  which can be attached to the free end of the rod without causing it to topple over.......solve ......... 

6 years ago

Answers : (1)

Sudheesh Singanamalla
114 Points
										

Since the unit of mass is not given ,


let us consider the mass of the rod of uniform length 1 m as 100Kg


since it is uniform each unit length has a mass of 1Kg


the edge of the table acts as the pivot of the rod.


so the mass of the 0.8m part is 80Kg and the 0.2m part hanging out has mass 20Kg


the normal force exerted at pivoted point is mg = 1000N


R - F1 - F2 =0


where R  is normal force at pivot , F1 is force at the 0.8m end on the table and F2 is the force that can be put on the free end


R = F1 + F2


1000 = 0.8 * 10 + 0.2 * M * g


200 = 20 M


M = 10Kg


therfore we can put 10Kg mass on the free end of the 0.2m part !


 


Please approve if it is right !

6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
Get extra Rs. 2,756 off
USE CODE: HRITHIK
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details
Get extra Rs. 2,968 off
USE CODE: HRITHIK

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details