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Chaitanya Borah Grade: 12
        


A particle P is sliding down a frictionless hemisphere bowl. it passes the point A at t=0. At this instant of time, the horizontal component of its velocity is v. A bead Q of the same mass as P is ejected from A at t=0 along horizontal spring AB with the speed v. Friction between bead and the string may be neglected. Let t(p) and t(q) be the respective times taken by P and Q tp reach the point B then


A. t(p)=t(q)


B. t(p)>t(q)


C. t(p)




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6 years ago

Answers : (3)

Sudheesh Singanamalla
114 Points
										

the mass of the particle P and the bead Q is the same and it is also given that they have the same velocity.


the object is a hemispherical bowl .


Let D1 be distance travelled by the particle P with mass m and velocity v.


D1 = vt


and D2 be the distance travelled by the bead Q with mass m and velocity v


since D2 is actually the displacement of Particle P and distance of bead B


we know displacement <= distance


displacement of P < distance travelled by P


==> distance travelled by bead Q < distance travelled by P


since velocity is the same.


time taken to travel a smaller distance is less than time taken to travel a larger distance.


therefore time taken by Particle P > time taken by bead Q


option B t(P) > t(Q) is the final answer


 


please approve if the answer is correct

6 years ago
upendra yadav
8 Points
										

SINCE THE VELOCITY COMPONENT IN THE HORIZONTAL DIRECTION IS SAME FOR BOTH THE BEADS AND THERE IS NO FRICTION IN BOTH THE PATHS . THEREFORE T(P)=T(Q).

6 years ago
shikhar
18 Points
										
question option are wrong
 
 
2 years ago
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