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rajan jha Grade: 12
        

265_23993_Photo0148.jpg

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

let its velocity  was v when it was in circular motion...after the string breaks , stone will move parabolically...


H = 2.7 (above the ground)


Ux= v       (velocity in circular path)


ay = -g


for horizontal motion threre is no accleration so ax =0


for verticle motion ,


S = gt2/2


2.7 = gt2/2


t = 0.74sec


now for horizontal motion


speed = distance/time


 Ux = 10/(0.74)                                   (distance 10m (given))


Ux = 13.51m/s


with this velocity particle was circulating .....


ac(centripital accleration) = v2/r = (13.51)2/1.5 = 122 m/s2

6 years ago
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