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rajan jha Grade: 12
        

1975_23993_Photo0147.jpg

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

let particle are at A,B,C...


force on A due to B is F & force on A due to C is also F...


F = Gm2/a2


net force  = (F2+F2+2F2cos@)1/2                                 (by vector method)


angle bw them is @ = 60


so net force = Fn = 31/2F       ...........1


due to this force ,each particle circulates aroung their center of mass & center of mass lies at the center of equilateral triangle ......


Fc = Fn = 31/2Gm2/a2   


mv2/r = 31/2Gm2/a2


  v = {31/2 Gm/a2r}1/2 


 now r = a/31/2        


 now v becomes


 v = {3Gm/a3}1/2                                             ans1


time period = 2pir/v


                =2pi(a/31/2){3Gm/a3)1/2


               = 2pi(gm/a)1/2                             ans2

6 years ago
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