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rajan jha Grade:
        

1994_23993_Photo0139.jpg

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

constan angular accleration = (alfa)                       (given)


w  =  wo + (alfa)t                    


w = (alfa)t                                     (wo = 0)


normal reaction bw rod & ring is ma ...                                          (a is linear accleration of rod at any time)


a = (alfa)r


N = m(alfa)r                 .......1


friction force (f) = uN = um(alfa)r     ...............2 


when this friction force is equal to centripital force then ring will slip


Fc(centripital force) = mw2r         .........3


equatin 2 & 3


 w2 = u(alfa)             ...........4


w = (alfa)t so above eq becomes


(alfa)2t2 = u(alfa)


      t2 = (u/alfa)


     t = (u/alfa)1/2

6 years ago
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