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rajan jha Grade: 12

A PARTICLE OF MASS M=3KG MOVES ALONG A ST.LINE 4y-3x=2 with constant velocity of 5m/s.The magnitude of angular momentum about origin is...........

6 years ago

## Answers : (2)

SAGAR SINGH - IIT DELHI
879 Points

Dear student,

You have to find perpendicular distance from orgin.

It will be 2/5.

Angular mom=mvr=3*5*2/5=6kgm2/s

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Askiitians Expert

Sagar Singh

B.Tech, IIT Delhi

6 years ago
vikas askiitian expert
510 Points

particle is moving along line 4y-3x = 2

perpendicular distance of line from origin = 4(0)-3(0)-2/(32+42)=2/5 units          (using property of line)

velocity of particle is 5m/s

angular momentam = mvrp                   (rp = perpendicular distance from line of motion to the point)

=3*5*2/5 = 6 units

6 years ago
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