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rajan jha Grade: 12
        

A THIN ROD OF LENGTH 1M IS FIXED IN A VERTICAL POSITION INSIDE A TRAIN, WHICH IS MOVING HORIZONTALLY WITH CONSTANT ACCELERATION 4M/S2. A BEAD CAN SLIDE ON THE ROAD AND FRICTION COEFFICIENT BETWEEN THEM IS 0.5. IF THE BEAD IS RELEASED FROM REST AT THE TOP OF THE ROD, IT WILL REACH THE BOTTOM IN ............................................. 

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

accleration of train = 4m/s2


bead will tend to move in horizontal direction due to seudo force = ma


normal reaction bw rod & bead = ma                  (a is accleration of train)


friction = u(N) = uma


weight = mg


net downward force = mg-uma


 m(net accleration) = m(g-ua)


     net accleration(A) = g - ua = 10-4*0.5 = 8m/s2


time taken by particle to reach the bottom is t


 s = At2/2                                (s=L =1m (given)


 1 = 8t2/2


t = 1/2 sec

6 years ago
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