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`        Two trains, each having speed 30 km/h, are headed at each other on the same straight track. A bird that can fly 60 km/h flies off the front of one train when they are 60 km apart. On reaching the other train, the bird directly flies back to the first train and so forth. What is the total distance the bird travels before the train collides?`
8 years ago

Ritika Chaudhury
18 Points
```										Ans: Total time interval for the birds motion = time taken for the trains to collide

ie t = initial seperation / velocity of approach
= 60/ 2(30)
= 1 hour

therfore, distance covered by bird = t.v
= 1.60 = 60 kms
```
8 years ago
manoj jangra
8 Points
```										hiii
when the train is 60 km apart bird flies
time taken by it to travel to other train
60t + 30t = 60
t = 2/3 hr
when bird reach othe train  distance between two trains = 20 km
time taken by it to travel to first train
60t + 30t = 20
t = 2/9 hr
this process will continue n times
so distance moved by bird = 60 x 2/3 +60 x 2/32 ................................60 x 2/3n
= 60 x 2/3 (1 + 1/3 + 1/32 ......................1/3n )
= 80/3 km    ....................          Ans

```
8 years ago
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