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Shivam Bhagat Grade: 9
        A particle moves along the side AB, BC, and CD, of a square of side 25m with a velocity of 15ms-1. Its average velocity is


(a) 15ms-1

(b) 10s-1

(c) 7.5ms-1

(d) 5ms-1

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

time taken by particle to cross any side = t


speed = d/t               (d is length of side)


t = 25/15 ..............1


now when particle moves from AB,BC,CD then it reaches to adjecent vertex D of square ...


total time taken = T = 3t =3(25/15) = 5sec


now average velocity = total displacement/total time


displacement BW initial poiny A & D is 25m so


average velocity  =  25/5 = 5m/s


option d is correct

6 years ago
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