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```        A particle moves along the side AB, BC, and CD, of a square of side 25m with a velocity of 15ms-1. Its average velocity is

(a)    15ms-1

(b)    10s-1

(c)    7.5ms-1

(d)    5ms-1

```
6 years ago

510 Points
```										time taken by particle to cross any side = t
speed = d/t               (d is length of side)
t = 25/15 ..............1
now when particle moves from AB,BC,CD then it reaches to adjecent vertex D of square ...
total time taken = T = 3t =3(25/15) = 5sec
now average velocity = total displacement/total time
displacement BW initial poiny A & D is 25m so
average velocity  =  25/5 = 5m/s
option d is correct
```
6 years ago
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