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aditya kulkarni Grade: 11
        a particle moving in a circle with a constant speed covers an angle of 90degrees .the change in its velocity is ??????in terms of v
6 years ago

Answers : (2)

AKASH GOYAL AskiitiansExpert-IITD
419 Points
										

Dear Aditya


In 90 degree it will cover one fourth of the perimeter


suppose speed is v then time taken t=2∏r/4v=∏r/2v


velocity=displacement/time


displacement=√r2+r2 =r√2


velocity=r√2/t = 2√2 v/∏


 


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AKASH GOYAL


AskiitiansExpert-IITD


 


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6 years ago
debdeep bhandari
14 Points
										

initial velocity is vi and final velocity is vj,,,,,so the net velocity is vj-vi,,,,whose magnitude is(v2+v2).5

6 years ago
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