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Jayati Dinesh Bharadwaj Grade: 10
        

A machine gun fires 25g bullates at the rate of 600 per minute with a speed of 400 m/s . Calculate the force required to keep the gun in position.

6 years ago

Answers : (2)

aditya suman
39 Points
										

Gun fires 600 bullets in 1 minute so,


no.of bullets fired in 1 second=10


now time taken by 1 bullet to get fired=1/10sec=0.1sec


initial velocity u=0m/s


final velocity v=400m/s


v=u+at 


400=0.1a


a=4000m/s2


now,force exerted by the bullet on the gun=force required to keep the gun in position


so,force exerted by 1 bullet f=ma=25*10-3*4000=100newtons


force exerted by 600 bullets=100*600=60000N                                                                 

6 years ago
Fawz Naim
37 Points
										

The mass of one bullet is 25g=25/1000 kg


velocity of each bullet = 400m/s


therefore the momentum of each bullet=25/1000*400


momentum of 600 bullets(P) =25/1000*400*600


initial momentum of the bullets is zero and the rate of change of momentum=force applied by the bullets on the gun


to balance this force an equal and opposite force is to be applied to keep the gun in position


therefore force=P/60


 

6 years ago
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