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`        A  machine gun fires 25g bullates at the rate of 600 per minute with a  speed of 400 m/s . Calculate the force required to keep the gun in  position. `
6 years ago

39 Points
```										Gun fires 600 bullets in 1 minute so,
no.of bullets fired in 1 second=10
now time taken by 1 bullet to get fired=1/10sec=0.1sec
initial velocity u=0m/s
final velocity v=400m/s
v=u+at
400=0.1a
a=4000m/s2
now,force exerted by the bullet on the gun=force required to keep the gun in position
so,force exerted by 1 bullet f=ma=25*10-3*4000=100newtons
force exerted by 600 bullets=100*600=60000N
```
6 years ago
Fawz Naim
37 Points
```										The mass of one bullet is 25g=25/1000 kg
velocity of each bullet = 400m/s
therefore the momentum of each bullet=25/1000*400
momentum of 600 bullets(P) =25/1000*400*600
initial momentum of the bullets is zero and the rate of change of momentum=force applied by the bullets on the gun
to balance this force an equal and opposite force is to be applied to keep the gun in position
therefore force=P/60

```
6 years ago
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