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`        A machine gun fires 25g bullates at the rate of 600 per minute with a speed of 400 m/s . Calculate the force required to keep the gun in position. plz explain thanks in advance.`
6 years ago

## Answers : (4)

419 Points
```										Dear JayatiForce=rate of change of momentum= dP/dt=d(mv)/dtF=v*dm/dt + m*dv/dthere v is constant hence dv/dt=0F=v*dm/dt600 bullets are fired in 60sechence in one second 600/60=10 bullets10 bullets=10x25=250 g= 0.25kgdm/dt=0.25 kg/secF=400x0.25= 100Nhence 100N force is to be applied on gun to keep it in the positionAll the best.                                                         AKASH GOYALAskiitiansExpert-IITDPlease feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation.Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar  respectively : Click here to download the toolbar..
```
6 years ago
kedar joshi
35 Points
```										hi,
force required to keep the gun in position will be rate of change of momentum
600 bullets are fired in in 1minute the in one second 10 bullets are fired.
hence rate of change of momentum of bullets is 25*10*400/1000 newtons
by calculation we get,
force required=rate of change of momentum of bullet=100N
please approve if you like the answer
```
6 years ago
510 Points
```										F = MvdN/dt
dN/dt = 600 per minute = 600 = 600/60 per second
=10 per sec
F = 25*10-3 *400*10
=100N
thus 100N force is required
```
6 years ago
Nitin Bindal
26 Points
```										By the law of conservation of momentum20*V=600*. 025*400V=300 m/sUsing equationV=u+atU=0m/s.  V=300m/s300=a*60.           1min=60seca=5m/s^2F=maF=20*5=100N
```
one year ago
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