Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```        A particle of mass m=5 is moving with uniform speed v=3√2 in the XY plane along the line y=x+4. The magnitude of angular momentum about origin is:
ans: 60

first of all, how can a body undergoing linear motion have angular momentum.

secondly, they have used L=mvr and taken r as 4/√2. How?```
6 years ago

Fawz Naim
37 Points
```										the body is undergoing rotational motion about the origin i.e. it is rotating in a circle having its centre as the origin and the radius is equal to the distance of that point from the origin. the distance of the given line from origin is 4/square root2
now the angular momentum can be calculated easily by putting the values
```
6 years ago
snehashish bal
21 Points
```										see one can calculate da angular momentum undergoing linear motion from da origin......nw u draw da coordinate axes and draw da line u ll find dat da prependicular distance of da origin to the line is 4/V2......
```
6 years ago
510 Points
```										 y = x+4               (given)
x-y+4 = 0
perpendicular distance from origen = 4/sqrt2=2sqrt2 m
now angular momentam = mvr                           (r is the perpendicular distance of line of motion of particle                                                                      & point about which we have  to calculate angular momentam)
=5*(3sqrt2)2sqrt2
=5*3*4
=60
```
6 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details