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`        a chain of lenght L is lying on a table with 1/3 of its lenght hanging down. Calculate the work done in pulling the chain up to the surface of table`
7 years ago

510 Points
```										this question can easily be solved if we consider the motion of center of mass of hanging part....
at intial moment L/3 length was hanging , so the distance of center of mass of this hanging part the from table is L/6...
mass of this hanging part = M/3
finally when the chain is pulled up then center of mass of hanging part is on table ....
workdone = mgdh                        (dh = change in height)
m = M/3 , h = L/6
work = M/3 *g* L/6
=MGL/18
.
```
7 years ago
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