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Calculate the height up to which an insect can crawl up a fixed bowl in form of a hemisphere of radius r. Given the coefficient of friction is 1/√3 .
Dear student,
just b4 slipping umgcostheta=mgsintheta tantheta=1/root3 theta=30 deg height=R(1-cos30) R(1-(root3)/2) Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar.. Askiitians Expert Sagar Singh B.Tech, IIT Delhi sagarsingh24.iitd@gmail.com
just b4 slipping
umgcostheta=mgsintheta
tantheta=1/root3
theta=30 deg
height=R(1-cos30)
R(1-(root3)/2)
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar.. Askiitians Expert Sagar Singh B.Tech, IIT Delhi sagarsingh24.iitd@gmail.com
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.
All the best.
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