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In a square field of side 10m, we move along two adjacent sides starting from one corner and ending at the opposite corner. What is our displacement.
Dear studentm
Displacement in this case= diagonal of the square=10 root 2 m
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Sagar Singh
B.Tech, IIT Delhi
sagarsingh24.iitd@gmail.com
let abcd be a square ...
if we from vertex a move along two adjecent sides then finally we reach to vertex c (the opposite vertex) ...
from pythogorus theorem
(ab)2+(bc)2 = (ac)2
ac is the displacement , ab = ac = 10 (each side is equal )
ac = root((ab)2+(bc)2)=(100+100)1/2
=(200)1/2m
(200)1/2 m is displacement
Let one side to be x
displacement = the minimum possible distance between 2 points of movement
therefore in a square according to problem, the displacement is the diagonal of that square
displacement is the distance between the initial and the final point. As we started from one vertex and stopped at the opposite vertex, so the displacement is equal to the length of the diagonal. Side of the square is 10m
therefore the length of the diagonal is =10*square root(2)
10*1.414=14.4m
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