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A particle projected from ground with speed u at an angle "a" with the horizontal. Radius of curvature of trajectory of the particle

5 years ago


Answers : (1)


Dear student,

Equation of Trajectory (Path of projectile)

At any instant t
x= ucosØ.t
» t= x/(ucosØ)

Also , y= usinØ.t - (1/2)gt2

Substituting for t
y= usinØ.x/(ucosØ) - (1/2)g[x/(ucosØ)]

» y= x.tanØ - [(1/2)g.sec2Ø.x2 ]/u2


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Sagar Singh

B.Tech, IIT Delhi

5 years ago

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