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Chanchal Kumar Grade: 11
        

Car A has an acceleration of 2 m/s^2 due east and car B, 4 m/s^2 due north. What is the acceleration of car B with respect to car A?

6 years ago

Answers : (3)

AKASH GOYAL AskiitiansExpert-IITD
419 Points
										

Dear Chanchal


aA=2i


aB=4j


rel acceleration = aB - aA= 4j-2i


magnitude=√42+22=√20 m/s2


direction=tan-1(4/2)=tan-12=63.430 from west towards north


All the best.


AKASH GOYAL


AskiitiansExpert-IITD


 


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6 years ago
vikas askiitian expert
510 Points
										

accleration of car A is a = 2i              (due to east)


accleration of car B is b =4j              (due to north)


accleration of B wrt A is arel = a-b


 arel = 2i - 4j


 a = (22+42)1/2 = 2(sqrt5)m/s2 in magnitude

6 years ago
Deepak Sharma
18 Points
										accleration of car A is a = 2i              (due to east)


accleration of car B is b =4j (due to north)

accleration of B wrt A is arel = a-b

arel = 2i - 4j

a = (22+42)1/2 = 2(sqrt5)m/s2 in magnitude


6 years ago
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