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Car A has an acceleration of 2 m/s^2 due east and car B, 4 m/s^2 due north. What is the acceleration of car B with respect to car A?
Dear Chanchal
aA=2i
aB=4j
rel acceleration = aB - aA= 4j-2i
magnitude=√42+22=√20 m/s2
direction=tan-1(4/2)=tan-12=63.430 from west towards north
All the best.
AKASH GOYAL
AskiitiansExpert-IITD
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accleration of car A is a = 2i (due to east)
accleration of car B is b =4j (due to north)
accleration of B wrt A is arel = a-b
arel = 2i - 4j
a = (22+42)1/2 = 2(sqrt5)m/s2 in magnitude
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