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`        Three blocks of masses 1kg,4kg,2kg are placed on a frictionless horizontal plane surface.two forces 120N and 50N are acting on the surface.120 N acts on the 1kg mass particle and 50 N acts in the opposite direction on 2kg masses.Find accelaration of the system.`
6 years ago

510 Points
```										net force on the system=120-50=70N
(total mass)(accleration)=70
7a=70
a=10m/s2 ans
```
6 years ago
Chiranjeevi .P
29 Points
```										a=F/m
a=(120-50)g/(1+4+2)
a=70g/7
a=10g
```
6 years ago
SAGAR SINGH - IIT DELHI
879 Points
```										Dear student,
In such type of questions first of all find the net force on the system.

Here in the question,
Net force on the system=120-50=70N
(total mass)(accleration)=70
7a=70
a=10m/s2
Hence acceleration of the system = 10 m/s2

All the best.
Win exciting gifts by answering the questions on Discussion Forum. So help discuss any                                  query on askiitians forum and become an   Elite        Expert        League            askiitian.

Sagar Singh
B.Tech, IIT Delhi

```
6 years ago
80 Points
```										BOTH ANSWER IS CORRECT.
```
6 years ago
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