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Parashar Chatterjee Grade: 11
        Three blocks of masses 1kg,4kg,2kg are placed on a frictionless horizontal plane surface.two forces 120N and 50N are acting on the surface.120 N acts on the 1kg mass particle and 50 N acts in the opposite direction on 2kg masses.Find accelaration of the system.
6 years ago

Answers : (4)

vikas askiitian expert
510 Points
										

net force on the system=120-50=70N


 (total mass)(accleration)=70


                  7a=70


                   a=10m/s2 ans

6 years ago
Chiranjeevi .P
29 Points
										

a=F/m


a=(120-50)g/(1+4+2)


a=70g/7


a=10g

6 years ago
SAGAR SINGH - IIT DELHI
879 Points
										

Dear student,


In such type of questions first of all find the net force on the system.



Here in the question,


Net force on the system=120-50=70N


 (total mass)(accleration)=70


                  7a=70


                   a=10m/s2


Hence acceleration of the system = 10 m/s2








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Sagar Singh


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6 years ago
Souradeep Majumder
80 Points
										

BOTH ANSWER IS CORRECT.

6 years ago
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