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manis kumar Grade: 12
        

The two blocks, m = 10kg and m = 50 kg are free to move as shown. The coefficient of static friction between the blocks Is 0.5 and there is no friction between M and the ground. A minimum horizontal force F is applied to hold m against M that is equal to

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

let the force applied on the block M of mass 50 kg is F...


 then


             F=(m+M)a


             a=F/(m+M)................1


now upper block will experience a seudo force of magnitude ma...


due to this seudo force it will tend to move but its  magnitude should be


greater than or equal to friction force...


seudo force>=friction force


ma >=umg


  a >=ug ............2


from eq 1


  F >= u(m+M)g


 F >=294N


so the minimum force is 294N


 

6 years ago
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