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harini v Grade: 11
`        a double star consists of two stars having masses m and 2m respsctively separated by a distance R.find the ratio of the kinetic energy of the bigger star to the smaller star ?`
7 years ago

## Answers : (2)

510 Points
```										here in the question ,we have two masses which are moving under the influence of their mutual gravitational force...
both of them are moving about their center of mass in a circular orbits of different radii..
if R1 & R2 are radius of lighter and heavior particle respectively then
R1 +R2 = R ................1
Fc =mW12 R1       ..................2              (gravitional force will provide necassery centripital force)
Fc=2mW22R2     .......................3
dividing 1 & 2
(W1/W2)2 =2(R2/R1) .............4
ratio of kinetic energy is (KE)2/(KE)1=2(W2/W1)2 (R2/R1)2
from eq 4 substituting (W2/W1)
ratio =2(R2/R1) ...................5
now we have R1=2mR/3m=2R/3   &  R2=mR/3m=R/3
after substituting these we get
ratio = 1:1
```
7 years ago
510 Points
```										see the eq 5 ,  the ratio instead of 2(R2/R1) ,it is  (R2/R1),
now u will will get ratio as 1:2 not 1:1 ...

sometimes calculations mistake may be there in the sol  ,so see the concept and do it urself ....
```
7 years ago
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