Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A ball of mass 50 kg is moving with a speed of 2m/s strikes a plane surface at an angle of incidence 45 degrees. the ball is reflected by the plane at an equal angle of reflection at the same speed. calculate (a) the magnitude of the change of momentum of the ball . (b)the change in the magnitude of the momentum of the ball`
6 years ago

510 Points
```										let ball is moving in x-y plane & approaching a wall at an angle45 degree which is placed in y-z plane...
initial momentam of ball is Pi =mvcos45 i  + mvsin45(-j)
finally it returnes at same angle & with same velocity so its final momntam is
Pf = mvcos45(-i) + mvsin45(-j)
change in momentam= Pi - Pi =2mvcos45
=21/2 mv
=100.21/2  or 100sqrt2  ans
approve if u like
```
6 years ago
Aman Bansal
592 Points
```										dear pooja singh ,
initially the ball s trikes theplanem akinganan gleof 45 degrees withthe plane and after the collision the ball makes an angleof45 degrees
then we canconserve momentum  in both the directions:
x-direction
(a)  magnitude of change in momentum =  50* 21/2
(b) but change in  magnitude =0
similarly,

y-direction
(a)  magnitude of change in momentum =  0
(b) but change in  magnitude =0

BEST OF LUCK
AMAN BANSAL

```
6 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
Get extra Rs. 1,860 off
USE CODE: SRIRAMA
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details
Get extra Rs. 1,860 off
USE CODE: SRIRAMA