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The work done in pulling body of mass 5kg along a inclined plane(angle 60 degree) with coefficient of friction 0.2 through 2 merter will be?
force of friction is down the incline
f=umgcos@
workdone by friction is Wf =umgcos@ds=-10
one component of weight is acting along incline downwards
Wmg = mgsin@ds=-50sqrt3
net workdone =change in kinetic energy
Wmg + Wf +W =0
W = -(Wmg + Wf)
W = (10+50sqrt3 )
W= 96.5 J
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