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Reyad Khaled Grade: Upto college level
        

For the following Fig. M=2 Kg and m=1kg . The horizontal surface is frictionless and the group move with constant acceleration (3.27 m/s2) and the mass less spring constant is 50 N/m. Find the distance stretched of the spring.


 


 


1033_24554_Figure Question.jpg

6 years ago

Answers : (2)

yudhvir maan
18 Points
										

FOR MASS m


mG-T=ma therefore T=6.73 N


FOR MASS M


F=Ma here mass =2kg and a=3.27


therefore F=6.54 N


F=kx where k=50 and x is elongation


x=6.54/50meter

6 years ago
Ashwani Goel
31 Points
										

ans.. is     1.8mm 



6 years ago
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