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distance of any corner from center is d =a/sqrt3... (a is side of triangle)
moment of inertia of system is I=(I1+I2+I3)
mass and distance from axis of rotation is same for all hree particles so I1=I2=I3
total moment of inertia I = 3I1 = md2 =3(0.1. a2 /3)=0.4kg-m2
hence option A is correct
all the masses are kept at a distance of 2/31/2 m from the axis at the centroid.
there fore m.i. of each mass at the axis willl be same i.e.=0.4/3kgm2 on adding all the three moments of inertia it =0.4kgm2
thus according to me the answer is <a> if its incorrect please send me the correct explanation if possible
plz solve my problem &give me list of reagents in org chem with there spatial feachers. !!!!!!!!!!!!!!!!!!!
plz help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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