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a particle of mass 1kg has a velocity of 2m/s. a constant force of 2 N acts on the particle for 1s in a direction perpendicular to its initial veiocity. find the velocity and displacement of the particle at the end of 1 second.
Dear Banjit
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AKASH GOYAL
AskiitiansExpert-IITD
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let particle is moving along x axis and force is acting along y axis....
F=ma
a=F/m=(2m/s2 ) j
v=2i (given)
for constant accleration we can use v=u+at and s=ut+at2 /2
after 1 sec
v=2i + 2j = 2sqrt2 in magnitude
s=2i+ j = sqrt5 in magnitude
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