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rajan jha Grade: 12
        

a figure is mentioned(as i don't know how 2 scrap images in the question) like that.


1)draw a base line


 2)a body B of mass 'm' on it


3) the upper end of B is attached to spring then with a string(rounded on a massless pulley)


4) the other part of the string is attached with a body A of mass M.


A  is released from rest when the string is in its natural length. for the block B to leave contact with the ground at some stage. what should be the minimum mass of block A  ??????????????

6 years ago

Answers : (1)

vinay AskiitiansExpert-IITD
34 Points
										

Dear Rajan,


you should analyze it that for minimum mass the block b will leave surface at maximum extension of spring, for masses greater, b will leave surface before maximum extension and for lesser masses it will not leave ever.


Let mass of block a  be M, we know at maximum extension velocity is 0 also extension in spring will be equal to desendent length  by block a


so by conservation of energy


    kx2 /2 = Mgx


    kx = 2Mg


now fbd of a


  kx-Mg = Ma


  gives  a = g


fbd of b with normal force 0 for leaving surface


ma = kx


mg = 2Mg


M = m/2


which is amaging that we can use 5kg to lift 10 kg wieght by putting a spring in between, otherwise we need to have 10 kg wieght.


like my answer.


For just leaving the surface the normal by surfce will be 0 on block b


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6 years ago
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