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rajan jha Grade: 12
        

 find the average velovity of a projectile projected with vekocity 'u'm/s making an angle "theta"  between its stsrting point and highest point?

6 years ago

Answers : (2)

AKASH GOYAL AskiitiansExpert-IITD
419 Points
										

Dear Rajan


See the pic for solution


All the best.


AKASH GOYAL


AskiitiansExpert-IITD


 


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285_23499_Photo-0089.jpg

6 years ago
vikas askiitian expert
510 Points
										

average velocity = total displacement / total time


H is the maximum height and R is the horizontal range of projectile ....


at highest point, projectile is H m above in verticle  and R/2 m  far in horizontal direction from the point of projection..


displacement = sqrt{ H^2 + (R/2)^2} ={u^2sin@ sqrt(1+3cos^2@) } /g


time taken by projectile to reach to maximum height is t = T/2 =usin@/g


Vavg = usqrt( 1+3cos^2@)

6 years ago
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