Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
find the average velovity of a projectile projected with vekocity 'u'm/s making an angle "theta" between its stsrting point and highest point?
Dear Rajan
See the pic for solution
All the best.
AKASH GOYAL
AskiitiansExpert-IITD
Please feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation.
Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar..
average velocity = total displacement / total time
H is the maximum height and R is the horizontal range of projectile ....
at highest point, projectile is H m above in verticle and R/2 m far in horizontal direction from the point of projection..
displacement = sqrt{ H^2 + (R/2)^2} ={u^2sin@ sqrt(1+3cos^2@) } /g
time taken by projectile to reach to maximum height is t = T/2 =usin@/g
Vavg = usqrt( 1+3cos^2@)
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !