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A particle is projected at an angle 60 degree,with speed 10sqrt3m/s from the Point A towards right.At the same time the wedge (HAVING ITS FOOT of inclination 30 degree at A) is made to move with speed 10sqrt3m/s towards right.Then the time after which the particle will strike with the wedge is
(a)2s
(b2sqrt3 m/s
(c)4/sqrt3 m/s
(d)none .............
dear Rajan
resolve the velocity of projectile
Ux= 10√3 COS60= 5√3
Uy=10√3 sin60=15
now you can see that horizontal velocity of wedge is more than the projectile hence they will not meet.
answer will be (d) none
All the best.
AKASH GOYAL
AskiitiansExpert-IITD
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