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Chilukuri Sai Kartik Grade: 12
        

The formula S=u+a(n-1/2) is dimensionally not correct.


But still we use it in variety of applications. Why do we still get the correct answer?


Please reply!!!

6 years ago

Answers : (5)

vikas askiitian expert
510 Points
										

Sn=un+an^2/2  ...........1               (displacement in n seconds)


Sn-1=u(n-1) +a(n-1)^2 /2.........2   (displacement in n-1 seconds)


 Snth=Sn-Sn-1


     Snth  =u + a(n-1/2) ..............3


in eq 1 , dimension of n is time and in eq 2 ,n-1 second that means 1 in n-1 second is having dimension of time......


1sec is a constant but it is having dimension ....so in same manner in eq 3 ,n-1/2 has dimension of time .....


so this relation is correct


approve my ans if u like

6 years ago
DIVYANK DUVEDI
33 Points
										

he you have taken this q frm dc pandey na

6 years ago
aakash
33 Points
										
a particle covers 10m in first 5s and 10m in next 3s. assuming constant acceleration find intial speed, acceleration , distance covered in next 2s.
2 years ago
PRAJVAL98
18 Points
										
it is dimentionally correct.
S in nth second in the sense u r talking about the diplacement in that second which will basically have the dimentional formula [M^0*L^1*T^-1]
the rhs also has the same dimentional formula.
 
                        prajval98
2 years ago
Karan sahu
24 Points
										St=(ut+1/2at2)-(u (t-1)+1/2a (t-1)2)=(u)(1)+1/2 (a)(2t)-1/2(a)(1)2the first term is (u)(1), which we are writing only u. Dimentions of u=[LT-1]and dimentions of 1 which we call 1 sec is [T]So, [(u)(1)]=[LT-1][T]=[L]=Sttherefore dimention of (u)(1) are same as the dimentions of St. Same logic can be applied with other terms too.👍👍
										
24 days ago
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