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NIKHIL GARG Grade: 12
        


Two particles A and B start fro rest and move for equal time on a straight line. The particle A has an acceleration a for first half of time and 2a for the second half. The particle B has an acceleration 2a for the second half. The particle B has an acceleration 2a for the first half and a for the second half. Which particle has covered larger distance?

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

particle A ( accleration a for first half and 2a for second half)


particle B ( accleration 2a for first half and a for second half)


let the total time for complete journey be T


for particle A


     for first half  time (T/2 , accleration a)


                                       S1=ut+at^2/2       (u=0)


                                      S1=aT^2/8....1


now particle has gained some velocity


      v=u+at


       v=aT/2


       for second half time (T/2 ,accleration 2a)


  S2=ut+2at^2/2


     S2=aT^2/2.........2


     S=S1+S2=5aT^2/8   .............1( total distance moved for particle A )


for particle B


  for first half t=T/2 ,accleration=2a


             S1=Ut+2at^2/2       (u=0)


              S1=aT^2/4


 now the particle is having velocity


         v=u+2at=2aT/2=aT


 for second half  t=T/2 ,accleration =a


              S2  =ut+at^2/2


                    =aT.T/2 + aT^2/8


                   =5aT^2/8


  S=S1+S2=7aT^2/8...............3 (total distance moved for particle B)


 so distance moved by B particle is greater

6 years ago
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