Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: R

There are no items in this cart.
Continue Shopping
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details
Get extra R 700 off


Is there something special when an object moves according to the law v=a*sqrt(s) ?

v -velocity

actually, the acceleration for this type of motion comes out to be constant.
= [a/2*sqrt(s)]*a.sqrt(s)=a^2/2
can you intuitively explain why this happens ?

6 years ago


Answers : (2)


v=ds/dt=Ksqrt(s)          (k=a^2/2)



 s=(kt+c)^2 /2

 it means graph between time and displacement is parabola......

6 years ago

 Hiii shubham



v = a root(x)


dx/dt = a.root(x)


dx/a.root(x) = a.dt

Integrate it ...


2root(x) = a .t


or   x = a^2.t^2/4


x = kt^2

This is a parabolic path with respect to time..

d^2x/dt^2 = 2k  ( constant )



So this is just a projectile motion with object starting from rest...moved with constant acceleration 2k





6 years ago

Post Your Answer

Other Related Questions on Mechanics

an object of maas m1 moving with speed V collide with anorther object of mass m2 at rest stick to it. find the impulse imparted to second object?
Let v1 be the combined velocity of both the bodies after collision. Momentum of the system before collision=m1v momentum of the system after collision =(m1+m2)v1 As the total momentum is...
Piyush Behera 10 days ago
From the momentum Conservation, m1v + 0 = (m1+m2)v’ v’ = m1v/(m1+m2) m/s. J = change in momentum ( for second object.) that is = > Pf – Pi => (m2)v’ - m2*0 => m1*m2*v/(m1+m2) N-m.
Vikas TU 10 days ago
Is there any book on theory of relative velocity of approach and separation
@ manju h c ver ma is the best one for that , it explains the relative velocity part in a little bit of detail by taking the example of diffrent scenario . so, u can use that , they also...
Umakant biswal 3 months ago
I think cengage physics mechanics-1 is the best because there is a complete explaination about all cases like minimum time of approach also angle of particles without using calculus and in...
benny bhai 3 months ago
DC Pandey explains the topic clearly andcan be very helpful to do problems related to relative velocity.So I would recommend you Mechanics-I by DC Pandey.
Mudit 3 months ago
A body is dropped from a height of 16 m The body strikes the ground and looses 25% of its velocity. The body rebounds to a height of ........
Let v be the velocity when it stri​kes the ground .ie final velocity ,then ​ v ​2 -0 ​2 ​=2*16*10=320,after rebound velocity V=3/4v,hight attained h=V ​2 ​/2*10=(3/4) ​2 ​...
abhi 3 months ago
When particle is dropped it will reached at ground with velocity √2gh OK.then it will rebounded with same velocity but of lose of energy it`s velocity becomes 0.75√2gh then after rebounded...
Praveen Mishra 2 months ago
calculate the value of the gas constant for one gram of hydrogen,given that density of hydrogen at N.T.P is 0.00009 g/cm 3
Density of hydrogen is at N.T.P condition 0.00009
OUTPASS one year ago
EXPERTS PLZ HELP ME Is the moment of inertia of disc and ring are (mr 2 )/2 and mr 2 respectively?? and if yes how can the moment of inetial of ring greater than that of disc ??
Yes, its true. The moment of inertia of a disc and a ring about an axis perpendicular to their plane are and resspectively. Here you have to notice in both the cases we are taking the mass...
Shaswata Biswas 29 days ago
See the moment of inertia is proportional to r 2, for same mass ,as the mass is concentrated more farther from the ring it will have greater moment of inertia.
Piyush Behera 9 days ago
why quantisation of charge has no significance at macroscopic level?
We know that every charge is a integral multiple of e (=1.6 * 10^(-19) C). While we dealing with charger like 1 microcolumb(order of magnitude of -6) or even nano columb this fact is not...
Ajmal Pt one year ago
shubham khanna one year ago
View all Questions »

  • Complete Physics Course - Class 12
  • OFFERED PRICE: R 2,600
  • View Details
Get extra R 650 off

  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details

Get extra R 700 off

More Questions On Mechanics

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!!
Click Here for details