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```
Is there something special when an object moves according to the law v=a*sqrt(s) ?
v -velocitya-constants-displacementactually, the acceleration for this type of motion comes out to be constant.dv/dt=dv/ds*ds/dt= [a/2*sqrt(s)]*a.sqrt(s)=a^2/2can you intuitively explain why this happens ?
```
7 years ago

510 Points
```										v=ds/dt=Ksqrt(s)          (k=a^2/2)
ds/sqrt(s)=kdt
2sqrts=kt+c
s=(kt+c)^2 /2
it means graph between time and displacement is parabola......
```
7 years ago
74 Points
```										 Hiii shubham

v = a root(x)

dx/dt = a.root(x)

dx/a.root(x) = a.dt
Integrate it ...

2root(x) = a .t

or   x = a^2.t^2/4

x = kt^2
This is a parabolic path with respect to time..
d^2x/dt^2 = 2k  ( constant )

So this is just a projectile motion with object starting from rest...moved with constant acceleration 2k

Regards
Yagya
```
7 years ago
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