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				   A block of mass 1kg moving with a speed 4m/s collides with another block of mass 2kg at rest,the light block comes to rest after collision,the loss in k.e. of the system is

6 years ago


Answers : (1)


m1u1=m1v1 + m2v2   (from conservation of momentam)

 1*4 =  2*v2 (v1=0 ..given)


 (kE)i =m1(u1)^2 /2


 (kE)f=m2(v2)^2 /2


 so kinetic energy transfered is 50%

6 years ago

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