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chakrala mounica Grade: 11
        A block of mass 1kg moving with a speed 4m/s collides with another block of mass 2kg at rest,the light block comes to rest after collision,the loss in k.e. of the system is
7 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

m1u1=m1v1 + m2v2   (from conservation of momentam)


 1*4 =  2*v2 (v1=0 ..given)


 v2=2m/s


 (kE)i =m1(u1)^2 /2


         =8joule


 (kE)f=m2(v2)^2 /2


       =4j


 so kinetic energy transfered is 50%

7 years ago
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