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let the mass of particle p be Mp and the mass of other particle q be Mq
let initial momentam of particle Pi
aplying conservation of momentam
Pi + o = Pf + Qf ......1 ( Pf,Qf are the momentam of P,q after collision)
by using p^2/2m = KE EQ 1 becomes
sqrt{(KE)pi. Mp} = sqrt{(KE)pf. Mp} + sqrt{(KE)qf.Mq}..........2
now applying conservation of total kinetic energy
(kinetic energy initially) (KE)pi +0 = (kE)pf +(kE)qf (final kinetic energy of p,q)
from the given data that 8/9 (kinetic energy of particle p) is transferred to particle q so now KE of p now is 1/9of initial
so (KE)pf =1/9 (kE)pi..........3
(KE)qf =8/9 (KE)pi..........4
putting values from 3,4 in eq 2
Mp/Mq =2
approve my ans if u like
sir please send me answers as fast as possible.
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