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sachin singh Grade: 12
        

A swimmer dived off a cliff with a running horizontal leap. What must his minimum speed be just as he leaves the top of the cliff so that he will miss the ledge at the bottom which is 2 m wide and 9 m below the top of the cliff?

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

time taken by swimmer to reach the ground is t


       s=uyt+at^2/2             (uy is verticle component of velocity of swimmer which is zero)


       s=9 and a=g=10


       so t=square root(2s/g)


             =3/root5 secs


  horizontal distance covered during this time is t.v (v is the velocity in horizontal direction)


    horizontal distance should be  2m so that he will mis the ledge


         vt=2


         v=2/t


           =2.root5/3 m/s


 

6 years ago
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