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```				   A 10kg block is placed on 40 kg block.a force of 200N is applied on small block.If  coefficient of static and kinetic friction are 0.4 and 0.6 respectively.then find the accelaration of the system.
```

6 years ago

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```										where is the friction acting between the blocks or between block and ground. check ur question how can coefficient of kinetic friction greater than static
```
6 years ago
```										at upper block  ,static friction force is less than force applied
so the kinetic friction now acts on the block
at upper block  ,
F-uk10g =10a
accleration of small block           a= 200-60/10=14
now this friction force becomes driving force for the bigger block
accleration of bigger block  a1=60/50=1.2

```
6 years ago

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