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Nitin Gupta Grade: 11
        

A bullet of mass 7g is fired into a block of metal of weight 7kg.The block is free to move.Calculate the velocity of bullet if the velocity of block with bullet is 0.7m/s.


Is the answer 350.35m/s?If not then provide the correct one


 

6 years ago

Answers : (3)

suryakanth AskiitiansExpert-IITB
105 Points
										

Dear nitin,


By considering the conservation of momentum


m1*V1 = (m1+m2)*v


finding V1,after substuting the values


m1= 7g


m2=7000g


v=0.7 m/s


we get V1=700.7 m/s





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Suryakanth –IITB




6 years ago
vikas askiitian expert
510 Points
										

applying conservation of momentam


     let intial velocity of bullet is Vb


 intial momentam=MbVb               Mb is the mass of bullet


 finally the whole system moves with velocity.7m/s


  final momentam=(M+Mb).7


                          =4.9049


intitial momentam = final momettam


so  Vb =4.9049/.007


         =700.7m/s

6 years ago
Karthik Eyan
45 Points
										

Mass of bullet = 7/1000 kg = 0.007 kg


Mass of block = 7 kg


Momentum is conserved in this case. So:


m1*u1 + m2*u2 = m1*v1 + m2*v2


m - mass [1 - bullet 2- block]


u - Initial velocity


v - final velocity


0.007*u1 = 4.9


u1 = 49/0.007


u1 = 7000 metre per sec.

6 years ago
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