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10g bullet is fired from a 5 kg gun with a velocity of 400 m/s.What is the speed of the recoil.

Is the answer -- 0.8m/s

If not then provide the correct solution

6 years ago


Answers : (4)


Dear nitin,

Your answer is correct

Vg = - (mb/mg)* Vb

    = - ((10* 10^(-3))/5) * 400

    = - (4/5)

    = - 0.8 m/s

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Askiitians Expert

Suryakanth –IITB

6 years ago

the answer 0.8m/s is correct.

6 years ago

it is correct, 

according to law of conservation of momentum,


v2 = m1v1/m2

v2 = (10x10-3)(400)/5

v2 = (0.01x400)/5

v2 = 4/5 = 0.8 ms-1


6 years ago

your ans is corect

 from conservation of momentam

  M1.V1 + mv2 =0



6 years ago

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