10g bullet is fired from a 5 kg gun with a velocity of 400 m/s.What is the speed of the recoil.
Is the answer -- 0.8m/s
If not then provide the correct solution
Approved Tutor Answer15 Years agoDear nitin,
Your answer is correct
Vg = - (mb/mg)* Vb
= - ((10* 10^(-3))/5) * 400
= - (4/5)
= - 0.8 m/s
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Suryakanth –IITB
Approved Tutor Answer15 Years agothe answer 0.8m/s is correct.
Approved Tutor Answer15 Years agoit is correct,
according to law of conservation of momentum,
m1v1=m2v2
v2 = m1v1/m2
v2 = (10x10-3)(400)/5
v2 = (0.01x400)/5
v2 = 4/5 = 0.8 ms-1
Approved Tutor Answer15 Years agoyour ans is corect
from conservation of momentam
M1.V1 + mv2 =0
V1=-mv2/M
=-4/5=-0.8m/s
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