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A body excutes SHM whose period is 16s.Two second after it passes the equilibrium position,its velocity is 1m/s.The amplitude of SHM is.
Dear Sunny,
as y = Asinwt
so, dy/dt = v = Awcoswt
here w = 2Π/T = Π/8 , v =1and t = 2
plug in all values
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Askiitians Expert
Anil Pannikar
IIT Bombay
x=Asinwt
thus v=dx/dt =Awcoswt (A is amplitude)
w is angular frequency =2pie/T =pie/8 (here T is time period)
w=pie/8
after 2 seconds its velocity is 1
1 =Awcoswt =awcospie/4
A=toot2/w=8root2/pie is required ans
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