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chakrala mounica Grade: 11
        A man throws balls with the same speed vertically upwards one after the other at an interval of 2seconds.What should be the speed of throw so that more than two balls are in the sky at any time?
6 years ago

Answers : (2)

Rathod Shankar AskiitiansExpert-IITB
69 Points
										

Dear chakrala mounica


the first has to be above the ground when the second ball is thrown from the ground


 


so the first ball has to be above from the ground for 2 seonds.


 


s=ut-1/2*gt^2        t=2  and s=0 when first ball reaches the ground


 


0= 2*u- 1/2*g*4


 


u=g m/s        take g=9.8 m/s^2


u= 9.8 m/s


 


speed has to be more than 9.8 m/s


 


 





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Askiitians Expert


Rathod Shankar Singh


IIT Bombay


 

6 years ago
Raunak Chaudhury
11 Points
										S=ut-1/2gt×t S=2u-19.6v^2=u^2-2aS0^2=u^2-2×9.8×(2u-19.6)0=u^2- 39.2u - (19.6)^20=(u- 19.6)^2u=19.6 m/secMore than 2 balls speed is greater than 19.6 m/sec
										
8 days ago
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