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`        A body dropped from a tall building covers,two floors in the first second.If all the floors are of equal height,the number of floors it covers in the next one second is`
7 years ago

85 Points
```										Dear Chakrala,

Let height of 1 floor is h,
u = 0 , so,  v  = u + at     (a = g =10 m/s2 )
v = 10 * 1 = 10 m/s
Now,    v2 - u2 = 2as
so,     100  = 2 * 10 * s
or,   s = 5 m
which implies height of each floor is  = 5 / 2 =  2.5 m
For 2 sec. , distance covered is  s= ut + 1/2 at2 = 0 + 10 * 4/2 = 20m
So, we have Distance covered in 2nd second = 20 - 5 = 15 m
Henc e, No. of floor = 15/2.5 = 6

All the best.
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IIT Bombay

```
7 years ago
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