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The potential energy of a 0.2 kg particle moving along the x axis is given by:

U(x) = 8x2 - 2x4

where U is in Joules and x in meters. When the particle is at x = 10 m, what will be its acceleration?

6 years ago


Answers : (1)


F = -du/dx 

   ={8x^3 - 16x}


 a=40(x^3 - 2x)

at x=10



6 years ago

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