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ankit sharma Grade: 12
        

The potential energy of a 0.2 kg particle moving along the x axis is given by:


U(x) = 8x2 - 2x4


where U is in Joules and x in meters. When the particle is at x = 10 m, what will be its acceleration?

7 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

F = -du/dx 


   ={8x^3 - 16x}


 F=ma


 a=40(x^3 - 2x)


at x=10


 a=3.92*10^4


 

7 years ago
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