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ankit sharma Grade: 12
        

A 0.2 kg rubber ball is dropped from the window of a building. It strikes the sidewalk below at 30 m/s and rebounds at 20 m/s. Find the change in momentum of the ball as a result of the collision with the side walk (in kg m/s).

6 years ago

Answers : (2)

OCEAN GODRE
40 Points
										

answer will be 2 kgm/s

6 years ago
vikas askiitian expert
510 Points
										

change in momentum =mdv


                                =m(Vf - Vi)


                                =.2(30-(-20))=10N.S

6 years ago
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