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```				   A truck is moving with a uniform velocity of 10 m/s.A leak occurs in the water tank of the truck at the rate of 2 kg/s.What is the speed of the truck after 50 seconds if the mass of the truck was 100 kg and mass of water in the tank initially was 100 kg?
```

6 years ago

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```										Assuming that the Truck is moving with constant Power (P), and assuming that F is the resistive force acting on the truck,
P = F x Velocity
P = (η xN) x 10, where η = dynamic friction, N = Normal Reaction = 200 kg xg
P =  η x 200g x 10...........(1)
After 50 seconds, the power remaining same,
P = η x 100g x V...........(2),  where V is the velocity after 100 Kg of water is unloaded in 50 seconds
Equating (1) and (2), Velocity V = 20 m/s
```
6 years ago
```
Dear Visheshh,
Assuming that the Truck is moving with constant Power (P), and assuming that F is the resistive force acting on the truck,
P = F x Velocity
P = (η xN) x 10, where η = dynamic friction, N = Normal Reaction = 200 kg xg
P =  η x 200g x 10...........(1)
After 50 seconds, the power remaining same,
P = η x 100g x V...........(2),  where V is the velocity after 100 Kg of water is unloaded in 50 seconds
Equating (1) and (2), Velocity V = 20 m/s

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```
6 years ago

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