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the bead is sliding vertically down with friction opposing its direction...
so net force on the bead vertically= M*g - z*N ....N=normal reaction force=M*a
& net horizontal foce = M*a
the normal foce would be..N=M*a (as N is in horizontal direction)
according tge cquestion.. the horizontal acce. =vertical acce.
=>(M*g - z*N ) /M = (M*a)/M
=>g - z*a = a
=>a =g/(1+z)
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