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```         A bead of mass M can slide on a thin vertical rod,with sliding friction coefficient between them=z. The rod is translated horizontally with a constant acceleration (a). For what value of (a) will an earth observer see equal horizotal and vertical components of acceleration of the bead?
```
7 years ago

sanki kurli
18 Points
```										the bead is sliding  vertically down with friction opposing its  direction...
so net force on the bead vertically= M*g -  z*N         ....N=normal reaction force=M*a
& net  horizontal foce = M*a
the normal foce would be..N=M*a    (as N is  in horizontal direction)
according tge cquestion.. the  horizontal acce. =vertical acce.
=>(M*g - z*N ) /M = (M*a)/M
=>g - z*a = a
=>a  =g/(1+z)
```
7 years ago
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