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PARTH ARORA Grade:
        

if v= (ax^2 + b)^ 0.5


 


would the variation of v with x be a x^2 type variation or a root X type variation??


i feel that it should depend on the value of constant a since d over dx of dv/dx can be negative or positive depending on value of a..


 


however the book says that it shuld be a x^2 type variation..


 


kindly help

6 years ago

Answers : (1)

Prudhvi teja
83 Points
										

Dear parth


a and b cant be negative


because it is defined for all x so


when x=0


v should exist so b>0


if a is negative at infinity v doesnt exist


so both a and b should exist.


and when look at graph you will get that it will have x2 variation



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Prudhvi Teja


 


 



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6 years ago
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