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if v= (ax^2 + b)^ 0.5
ย
would the variation of v with x be a x^2 type variation or a root X type variation??
i feel that it should depend on the value of constant a since d over dx of dv/dx can be negative or positive depending on value of a..
however the book says that it shuld be a x^2 type variation..
kindly help
Dear parth
a and b cant be negative
because it is defined for all x so
when x=0
v should exist so b>0
if a is negative at infinity v doesnt exist
so both a and b should exist.
and when look at graph you will get that it will have x2 variation
Please feel free to post as many doubts on our discussion forum as you can.we will get you the answer and detailed solution very quickly.All the best. Regards,Askiitians ExpertsPrudhvi Teja Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian
Please feel free to post as many doubts on our discussion forum as you can.we will get you the answer and detailed solution very quickly.All the best.
Regards,Askiitians ExpertsPrudhvi Teja
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