Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```        Two smooth spheres "A" and "B" are at opposite sides of a diameter of a circular smooth tube of radius R. The tube is placed on horizontal floor. At t=0 sphere "A" moves with constant angular velocity "w" and "B" with "2w" in the clockwise direction.During collission the velocities are exchanged.
a) Find the time taken for first second and third collission.
b) Find the distance travelled by the sphere "A" before second collission```
7 years ago

68 Points
```										Dear ajit ,
you can apply the concept of relative velocity in case of angular motion also. so here the angular velocityof b w.rt a is w in clockwise direction.
therefore
a) for first collision - time taken is the time when the body b moves a full circle w.r.t to a if we are applying relative concepts ....... so  wrelative   = vrelative/R ; wrelative   =  R/Rt1 ;    t1  =1 / wrelative
therefore  t1 =  1/w
for third collision : consider the scenario when the first hit takes , the velocities are exchanged i.e the angular velocities are also exchanged . so now A has 2w and B has w as angular velocity. so now in the same time A will hit B from behind. So , taking symmetry third collision shud take 3t1   as time. therefore  t3 = 3t1.  i.e  3/w
b)before first collision the angular velocity of A was w . so distance travelled  =  velocity * t1
=   wR * 1/w =    R
between first and second collision -- distance travelled  =  2WR*1/w =  2R
so total distance travelled  =  3R

Please feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation. Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
```
7 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
Get extra Rs. 551 off
USE CODE: CHEM20
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details
Get extra Rs. 594 off
USE CODE: CHEM20