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SIR,


WHAT IS THE BASIC APPROACH TO DERIVE EQUATION OF TRAJECTORY IN a)projectile motion  b)river swimmer cases.


what is the use of above eqn. ?


WHAT IS EQN. OF PARABOLA?


WHEN DO WE PERFORM DIFFERENTIATION & WHEN INTEGRATION IN PROBLEMS OF WPE, LAWS OF MOTION & KINEMATICS ?


SAUMYA SHIVHARE

6 years ago

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Answers : (2)

										

Dear saumya


basic approach is


let angle be b


then vertical velocity = usinp


horizontal = ucosp


y= (usinp)t-1/2 gt^2


x= ucospt


now use t from second equation in first


you cna get equation


any equation in form of y= ax2+bx+c is form of parabola


differentioan is when you wnat to find out velocity from displacement or accelerationfrom velocity


integration is just opposite to differentiation



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6 years ago
										

Hi ,


Steps to solve problems involving trajectory : 


Resolve components of velocity and acceleration along X and Y direction taking care of sign.


Then use the three laws of motion.


If the acceleration varies use differential forms and then integrate the expression suitably.


You can directly get relation between x and y or will get in terms of t.


Eliminate t to get expression for trajectory. 
 


These steps are applicable in all kinds of motion involving trajectory.

6 years ago

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