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A small particle of mass m attached with a light inextensible thread of length L is moving in vertical circle.Minimum velocity requried for the particle to go around complete vertical circle is √gL.In the given case particle is moving in a complete vertical circle and ratio of its maximum to minimum velocity is 2:1.Find the minimum velocity of particle_______________________
Dear Sindhuja,
Ans:- Let the max velocity is 2u then the min velocity is u(at the topmost point) then from the law of conservation of energy we get,
(2u)²=u²+2g(2L)
or 3u²=4gL
Hence u=2√(gL/3)
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